Can you disprove the following theorem where 2 = 4 ?
1) 9 = 9
2) -8 + 9 = -8 + 9 //Adding -8 to both sides
3) (4-12) + 9 = (16-24) + 9 //Splitting 8 on both sides as substraction of two numbers
3) 2(2) -2(2)(3) + 9 = 4(4) – 2(4)(3) + 9 //Writing out the numbers in the form of a^2 -2ab + b^2
4) (2-3)^2 = (4-3)^2 // a^2-2ab+b^2 = (a-b)^2
5) 2-3 = 4-3 //After taking square root of both sides
6) 2 = 4 //Cancelling out the common factor
a^2 = b^2 does not imply a = b necessarily. Only one of the following is true: a = b; a = -b.
And the winner of this puzzle round is (drumroll in the background)… Sanket.